A series LCR circuit is subjected to an ac signal of $200 \mathrm{~V}, 50 \mathrm{~Hz}$. If the voltage across the inductor $(\mathrm{L}=10 \mathrm{~mH})$ is $31.4 \mathrm{~V}$, then the current in this circuit is _______.
Solution
<p>$$\begin{aligned}
&V_L=I(\omega L)=31.4\\
&\begin{aligned}
\Rightarrow \quad I & =\frac{31.4}{2 \times 3.14 \times 50 \times 10 \times 10^{-3}} \\
& =10 \mathrm{~A}
\end{aligned}
\end{aligned}$$</p>
About this question
Subject: Physics · Chapter: Alternating Current · Topic: AC Circuits: R, L, C
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