A sinusoidal voltage of peak value 250 V is applied to a series LCR circuit, in which R = 8$\Omega$, L = 24 mH and C = 60 $\mu$F. The value of power dissipated at resonant condition is 'x' kW. The value of x to the nearest integer is ____________.
Answer (integer)
4
Solution
At resonance power (P)<br><br>$P = {{{{({V_{rms}})}^2}} \over R}$<br><br>$\therefore$ $P = {{{{(250/\sqrt 2 )}^2}} \over 8}$<br><br>$\Rightarrow$ P = 3906.25 w<br><br>$\Rightarrow$ P $\cong$ 4 Kw
About this question
Subject: Physics · Chapter: Alternating Current · Topic: AC Circuits: R, L, C
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