An inductor of inductance 2 $\mathrm{\mu H}$ is connected in series with a resistance, a variable capacitor and an AC source of frequency 7 kHz. The value of capacitance for which maximum current is drawn into the circuit $\frac{1}{x}\mathrm{F}$, where the value of $x$ is ___________.
(Take $\pi=\frac{22}{7}$)
Answer (integer)
3872
Solution
<p>Current drawn is maximum when circuit is in resonance.</p>
<p>$\omega = {1 \over {\sqrt {LC} }}$</p>
<p>$2\pi (7000) = {1 \over {\sqrt {2 \times {{10}^{ - 6}}C} }}$</p>
<p>$\Rightarrow C = {1 \over {3872}}F$</p>
About this question
Subject: Physics · Chapter: Alternating Current · Topic: AC Circuits: R, L, C
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