A direct current of $4 \mathrm{~A}$ and an alternating current of peak value $4 \mathrm{~A}$ flow through resistance of $3\, \Omega$ and $2\,\Omega$ respectively. The ratio of heat produced in the two resistances in same interval of time will be :
Solution
<p>Ratio = $${{i_1^2{R_1}} \over {{{\left( {{{{i_2}} \over {\sqrt 2 }}} \right)}^2}{R_2}}} = {{{4^2} \times 3} \over {{{\left( {{4 \over {\sqrt 2 }}} \right)}^2} \times 2}}$$</p>
<p>$\Rightarrow$ Ratio = 3 : 1</p>
About this question
Subject: Physics · Chapter: Alternating Current · Topic: AC Circuits: R, L, C
This question is part of PrepWiser's free JEE Main question bank. 115 more solved questions on Alternating Current are available — start with the harder ones if your accuracy is >70%.