An inductor of $0.5 ~\mathrm{mH}$, a capacitor of $20 ~\mu \mathrm{F}$ and resistance of $20 ~\Omega$ are connected in series with a $220 \mathrm{~V}$ ac source. If the current is in phase with the emf, the amplitude of current of the circuit is $\sqrt{x}$ A. The value of $x$ is ___________
Answer (integer)
242
Solution
$X_L=X_C$
<br/><br/>So, $\mathrm{Z}=\mathrm{R}=20 \Omega$
<br/><br/>$$
\begin{aligned}
& \mathrm{i}_{\mathrm{rms}}=\frac{220}{20}=11 \\\\
& \mathrm{i}_{\max }=11 \sqrt{2}=\sqrt{242}
\end{aligned}
$$
About this question
Subject: Physics · Chapter: Alternating Current · Topic: AC Circuits: R, L, C
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