An AC circuit has R= 100 $\Omega$, C = 2 $\mu$F and L = 80 mH, connected in series. The quality factor of the circuit is :
Solution
$Q = {1 \over R}\sqrt {{L \over C}}$
<br><br>= $${1 \over {100}}\sqrt {{{80 \times {{10}^{ - 3}}} \over {2 \times {{10}^{ - 6}}}}} $$
<br><br>= ${1 \over {100}}\sqrt {40 \times {{10}^3}}$
<br><br>= ${{200} \over {100}}$ = 2
About this question
Subject: Physics · Chapter: Alternating Current · Topic: AC Circuits: R, L, C
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