A sinusoidal voltage V(t) = 210 sin 3000 t volt is applied to a series LCR circuit in which L = 10 mH, C = 25 $\mu$F and R = 100 $\Omega$. The phase difference ($\Phi$) between the applied voltage and resultant current will be :
Solution
<p>${X_L} = 3000 \times 10 \times {10^{ - 3}} = 30\,\Omega$</p>
<p>${X_C} = {1 \over {3000 \times 25}} \times {10^6} = {{40} \over 3}\,\Omega$</p>
<p>So ${X_L} - {X_C} = 30 - {{40} \over 3} = {{50} \over 3}\,\Omega$</p>
<p>$\tan \theta = {{{X_L} - {X_C}} \over R} = {{50/3} \over {100}} = {1 \over 6}$</p>
<p>So $\theta = {\tan ^{ - 1}}(0.17)$</p>
About this question
Subject: Physics · Chapter: Alternating Current · Topic: AC Circuits: R, L, C
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