In an ac generator, a rectangular coil of 100 turns each having area $14 \times 10^{-2} \mathrm{~m}^{2}$ is rotated at $360 ~\mathrm{rev} / \mathrm{min}$ about an axis perpendicular to a uniform magnetic field of magnitude $3.0 \mathrm{~T}$. The maximum value of the emf produced will be ________ $V$.
$\left(\right.$ Take $\left.\pi=\frac{22}{7}\right)$
Answer (integer)
1584
Solution
<p>$\phi=B.A$</p>
<p>$\phi=\mathrm{BNA}\cos\omega t$</p>
<p>So, $Emf = {{ - d\phi } \over {dt}} = NBA\omega \sin \omega t$</p>
<p>So maximum value of emf is</p>
<p>${E_{\max }} = NBA\omega$</p>
<p>$$ = 100 \times 3 \times 14 \times {10^{ - 2}} \times {{360 \times 2\pi } \over {60}} = 1584$$</p>
About this question
Subject: Physics · Chapter: Alternating Current · Topic: AC Circuits: R, L, C
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