Primary side of a transformer is connected to $230 \mathrm{~V}, 50 \mathrm{~Hz}$ supply. Turns ratio of primary to secondary winding is $10: 1$. Load resistance connected to secondary side is $46 \Omega$. The power consumed in it is :
Solution
<p>$$\begin{aligned}
& \frac{V_1}{V_2}=\frac{N_1}{N_2} \\
& \frac{230}{V_2}=\frac{10}{1} \\
& V_2=23 \mathrm{~V}
\end{aligned}$$</p>
<p>Power consumed $=\frac{\mathrm{V}_2^2}{\mathrm{R}}$</p>
<p>$=\frac{23 \times 23}{46}=11.5 \mathrm{~W}$</p>
About this question
Subject: Physics · Chapter: Alternating Current · Topic: AC Circuits: R, L, C
This question is part of PrepWiser's free JEE Main question bank. 115 more solved questions on Alternating Current are available — start with the harder ones if your accuracy is >70%.