Medium INTEGER +4 / -1 PYQ · JEE Mains 2021

In a series LCR resonant circuit, the quality factor is measured as 100. If the inductance is increased by two fold and resistance is decreased by two fold, then the quality factor after this change will be __________.

Answer (integer) 283

Solution

Quality factor = ${{{X_L}} \over R} = {{\omega L} \over R}$<br><br>$Q = {1 \over {\sqrt {LC} }}{L \over R}$<br><br>$Q = \left( {{1 \over {\sqrt C }}} \right){{\sqrt L } \over R}$<br><br>$$Q = {{XL} \over R} = {{\omega L} \over R} = {1 \over {\sqrt {LC} }}{L \over R} = {1 \over R}{{\sqrt L } \over {\sqrt C }}$$<br><br>$Q' = {{\sqrt {2L} } \over {\left( {{R \over 2}} \right)\sqrt C }} = 2\sqrt 2 Q$<br><br>Q' = 282.84

About this question

Subject: Physics · Chapter: Alternating Current · Topic: AC Circuits: R, L, C

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