In a series LCR resonant circuit, the quality factor is measured as 100. If the inductance is increased by two fold and resistance is decreased by two fold, then the quality factor after this change will be __________.
Answer (integer)
283
Solution
Quality factor = ${{{X_L}} \over R} = {{\omega L} \over R}$<br><br>$Q = {1 \over {\sqrt {LC} }}{L \over R}$<br><br>$Q = \left( {{1 \over {\sqrt C }}} \right){{\sqrt L } \over R}$<br><br>$$Q = {{XL} \over R} = {{\omega L} \over R} = {1 \over {\sqrt {LC} }}{L \over R} = {1 \over R}{{\sqrt L } \over {\sqrt C }}$$<br><br>$Q' = {{\sqrt {2L} } \over {\left( {{R \over 2}} \right)\sqrt C }} = 2\sqrt 2 Q$<br><br>Q' = 282.84
About this question
Subject: Physics · Chapter: Alternating Current · Topic: AC Circuits: R, L, C
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