If the sum of solutions of the system of equations $2 \sin ^{2} \theta-\cos 2 \theta=0$ and $2 \cos ^{2} \theta+3 \sin \theta=0$ in the interval $[0,2 \pi]$ is $k \pi$, then $k$ is equal to __________.
Answer (integer)
3
Solution
<p>Equation (1) $~~~2{\sin ^2}\theta = 1 - 2{\sin ^2}\theta$</p>
<p>$\Rightarrow {\sin ^2}\theta = {1 \over 4}$</p>
<p>$\Rightarrow \sin \theta = \, \pm \,{1 \over 2}$</p>
<p>$$ \Rightarrow \theta = {\pi \over 6},{{5\pi } \over 6},{{7\pi } \over 6},{{11\pi } \over 6}$$</p>
<p>Equation (2) $~~~2{\cos ^2}\theta + 3\sin \theta = 0$</p>
<p>$\Rightarrow 2{\sin ^2}\theta - 3\sin \theta - 2 = 0$</p>
<p>$\Rightarrow 2{\sin ^2}\theta - 4\sin \theta + \sin \theta - 2 = 0$</p>
<p>$\Rightarrow (\sin \theta - 2)(2\sin \theta + 1) = 0$</p>
<p>$\Rightarrow \sin \theta = {{ - 1} \over 2}$</p>
<p>$\Rightarrow \theta = {{7\pi } \over 6},{{11\pi } \over 6}$</p>
<p>$\therefore$ Common solutions $= {{7\pi } \over 6};\,{{11\pi } \over 6}$</p>
<p>Sum of solutions $= {{7\pi + 11\pi } \over 6} = {{18\pi } \over 6} = 3\pi$</p>
<p>$\therefore$ $k = 3$</p>
About this question
Subject: Mathematics · Chapter: Trigonometric Functions · Topic: Trigonometric Ratios and Identities
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