If m and n respectively are the numbers of positive and negative values of $\theta$ in the interval $[-\pi,\pi]$ that satisfy the equation $\cos 2\theta \cos {\theta \over 2} = \cos 3\theta \cos {{9\theta } \over 2}$, then mn is equal to ____________.
Answer (integer)
25
Solution
$2 \cos 2 \theta \cos \frac{\theta}{2}=2 \cos 3 \theta \cos \frac{9 \theta}{2}$
<br/><br/>
$$
\begin{aligned}
& \cos \frac{5 \theta}{2}+\cos \frac{3 \theta}{2}=\cos \frac{15 \theta}{2}+\cos \frac{3 \theta}{2} \\\\
& \cos \frac{5 \theta}{2}=\cos \frac{15 \theta}{2} \\\\
& \frac{15 \theta}{2}=2 n \pi \pm \frac{5 \theta}{2} \\\\
& \frac{15 \theta}{2} \pm \frac{5 \theta}{2}=2 n \pi \\\\
& 10 \theta=2 n \pi \quad \text { or } 5 \theta=2 n \pi \\\\
& \theta=\frac{n \pi}{5} \text { or } \theta=\frac{2 n \pi}{5} \\\\
& \Rightarrow \theta=\frac{n \pi}{5}
\end{aligned}
$$<br/><br/>
$$
\begin{aligned}
& \theta=\pm \pi, \pm \frac{4 \pi}{5}, \pm \frac{3 \pi}{5}, \pm \frac{2 \pi}{5}, \pm \frac{\pi}{5} \\\\
& m=5, \quad n=5 \\\\
& m n=25
\end{aligned}
$$
About this question
Subject: Mathematics · Chapter: Trigonometric Functions · Topic: Trigonometric Ratios and Identities
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