Consider the following frequency distribution :
| Class : | 10-20 | 20-30 | 30-40 | 40-50 | 50-60 |
|---|---|---|---|---|---|
| Frequency : | $\alpha$ | 110 | 54 | 30 | $\beta$ |
If the sum of all frequencies is 584 and median is 45, then | $\alpha$ $-$ $\beta$ | is equal to _______________.
Answer (integer)
164
Solution
$\because$ Sum of frequencies = 584<br><br>$\Rightarrow$ $\alpha$ + $\beta$ = 390<br><br>Now, median is at ${{584} \over 2}$ = 292<sup>th</sup><br><br>$\because$ Median = 45 (lies in class 40 - 50)<br><br>$\Rightarrow$ $\alpha$ + 110 + 54 + 15 = 292<br><br>$\Rightarrow$ $\alpha$ = 113, $\beta$ = 277<br><br>$\Rightarrow$ | $\alpha$ $-$ $\beta$ | = 164
About this question
Subject: Mathematics · Chapter: Statistics · Topic: Measures of Central Tendency
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