Easy INTEGER +4 / -1 PYQ · JEE Mains 2024

The variance $\sigma^2$ of the data

$x_i$ 0 1 5 6 10 12 17
$f_i$ 3 2 3 2 6 3 3

is _________.

Answer (integer) 29

Solution

<p><style type="text/css"> .tg {border-collapse:collapse;border-spacing:0;} .tg td{border-color:black;border-style:solid;border-width:1px;font-family:Arial, sans-serif;font-size:14px; overflow:hidden;padding:10px 5px;word-break:normal;} .tg th{border-color:black;border-style:solid;border-width:1px;font-family:Arial, sans-serif;font-size:14px; font-weight:normal;overflow:hidden;padding:10px 5px;word-break:normal;} .tg .tg-baqh{text-align:center;vertical-align:top} </style> <table class="tg" style="undefined;table-layout: fixed; width: 519px"> <colgroup> <col style="width: 94px"> <col style="width: 123px"> <col style="width: 99px"> <col style="width: 203px"> </colgroup> <thead> <tr> <th class="tg-baqh">$\mathrm{x_i}$</th> <th class="tg-baqh">$\mathrm{f_i}$</th> <th class="tg-baqh">$\mathrm{f_i x_i}$</th> <th class="tg-baqh">$\mathrm{f_i x^2_i}$</th> </tr> </thead> <tbody> <tr> <td class="tg-baqh">0</td> <td class="tg-baqh">3</td> <td class="tg-baqh">0</td> <td class="tg-baqh">0</td> </tr> <tr> <td class="tg-baqh">1</td> <td class="tg-baqh">2</td> <td class="tg-baqh">2</td> <td class="tg-baqh">2</td> </tr> <tr> <td class="tg-baqh">5</td> <td class="tg-baqh">3</td> <td class="tg-baqh">15</td> <td class="tg-baqh">75</td> </tr> <tr> <td class="tg-baqh">6</td> <td class="tg-baqh">2</td> <td class="tg-baqh">12</td> <td class="tg-baqh">72</td> </tr> <tr> <td class="tg-baqh">10</td> <td class="tg-baqh">6</td> <td class="tg-baqh">60</td> <td class="tg-baqh">600</td> </tr> <tr> <td class="tg-baqh">12</td> <td class="tg-baqh">3</td> <td class="tg-baqh">36</td> <td class="tg-baqh">432</td> </tr> <tr> <td class="tg-baqh">17</td> <td class="tg-baqh">3</td> <td class="tg-baqh">51</td> <td class="tg-baqh">867</td> </tr> <tr> <td class="tg-baqh"></td> <td class="tg-baqh">$\Sigma \mathrm{f}_{\mathrm{i}}=22$</td> <td class="tg-baqh"></td> <td class="tg-baqh">$\Sigma \mathrm{f}_{\mathrm{i}} \mathrm{x}_{\mathrm{i}}^2=2048$</td> </tr> </tbody> </table></p> <p>$$\begin{aligned} & \therefore \quad \Sigma \mathrm{f}_{\mathrm{i}} \mathrm{X}_{\mathrm{i}}=176 \\ & \text { So } \overline{\mathrm{x}}=\frac{\sum \mathrm{f}_{\mathrm{i}} \mathrm{x}_{\mathrm{i}}}{\sum \mathrm{f}_{\mathrm{i}}}=\frac{176}{22}=8 \\ & \text { for } \sigma^2=\frac{1}{\mathrm{~N}} \sum \mathrm{f}_{\mathrm{i}} \mathrm{x}_{\mathrm{i}}{ }^2-(\overline{\mathrm{x}})^2 \\ & =\frac{1}{22} \times 2048-(8)^2 \\ & =93.090964 \\ & =29.0909 \\ & \end{aligned}$$</p>

About this question

Subject: Mathematics · Chapter: Statistics · Topic: Measures of Central Tendency

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