Medium MCQ +4 / -1 PYQ · JEE Mains 2023

Three rotten apples are mixed accidently with seven good apples and four apples are drawn one by one without replacement. Let the random variable X denote the number of rotten apples. If $\mu$ and $\sigma^2$ represent mean and variance of X, respectively, then $10(\mu^2+\sigma^2)$ is equal to :

  1. A 20 Correct answer
  2. B 30
  3. C 250
  4. D 25

Solution

<p>3 rotten apples are mixed with 7 good apples.</p> <p>$\therefore$ Total apples = 10</p> <p>Among those 10 apples 4 are chosen randomly.</p> <p><style type="text/css"> .tg {border-collapse:collapse;border-spacing:0;} .tg td{border-color:black;border-style:solid;border-width:1px;font-family:Arial, sans-serif;font-size:14px; overflow:hidden;padding:10px 5px;word-break:normal;} .tg th{border-color:black;border-style:solid;border-width:1px;font-family:Arial, sans-serif;font-size:14px; font-weight:normal;overflow:hidden;padding:10px 5px;word-break:normal;} .tg .tg-c3ow{border-color:inherit;text-align:center;vertical-align:top} .tg .tg-7btt{border-color:inherit;font-weight:bold;text-align:center;vertical-align:top} </style> <table class="tg" style="undefined;table-layout: fixed; width: 575px"> <colgroup> <col style="width: 52px"> <col style="width: 196px"> <col style="width: 93px"> <col style="width: 234px"> </colgroup> <thead> <tr> <th class="tg-7btt">${x_i}$</th> <th class="tg-7btt">${p_i}$<br></th> <th class="tg-7btt">${p_i}{x_i}$</th> <th class="tg-7btt">${p_i}{({x_i})^2}$<br></th> </tr> </thead> <tbody> <tr> <td class="tg-c3ow">0</td> <td class="tg-c3ow">${{{}^7{C_4}} \over {{}^{10}{C_4}}} = {{35} \over {210}}$</td> <td class="tg-c3ow">0</td> <td class="tg-c3ow">0</td> </tr> <tr> <td class="tg-c3ow">1</td> <td class="tg-c3ow">${{{}^3{C_1} \times {}^7{C_3}} \over {{}^{10}{C_4}}} = {{105} \over {210}}$</td> <td class="tg-c3ow">${{105} \over {210}}$</td> <td class="tg-c3ow">${{105} \over {210}}$</td> </tr> <tr> <td class="tg-c3ow">2</td> <td class="tg-c3ow">${{{}^3{C_2} \times {}^7{C_2}} \over {{}^{10}{C_4}}} = {{63} \over {210}}$</td> <td class="tg-c3ow">${{126} \over {210}}$</td> <td class="tg-c3ow">${{252} \over {210}}$</td> </tr> <tr> <td class="tg-c3ow">3</td> <td class="tg-c3ow">${{{}^3{C_3} \times {}^7{C_1}} \over {{}^{10}{C_4}}} = {7 \over {210}}$</td> <td class="tg-c3ow">${{21} \over {210}}$</td> <td class="tg-c3ow">${{63} \over {210}}$</td> </tr> </tbody> </table></p> <p>${x_i}$ = Number of rotten apples drawn.</p> <p>${p_i}$ = Probability of rotten apple.</p> <p>We know,</p> <p>Mean $(\mu ) = \sum {{p_i}{x_i}}$</p> <p>$= 0 + {{105} \over {210}} + {{126} \over {210}} + {{21} \over {210}}$</p> <p>$= {{252} \over {210}} = {6 \over 5}$</p> <p>Also,</p> <p>Variance $({\sigma ^2}) = \left( {\sum {{p_i}{{({x_i})}^2}} } \right) - {\mu ^2}$</p> <p>$$ = {{105} \over {210}} + {{252} \over {210}} + {{63} \over {210}} - {{36} \over {25}}$$</p> <p>$$ = {1 \over 2} + {{12} \over {10}} + {3 \over {10}} - {{36} \over {25}} = {{14} \over {25}}$$</p> <p>$\therefore$ $10(\mu^2 + {\sigma ^2})$</p> <p>$= 10\left( {({6 \over 5})^2 + {{14} \over {25}}} \right)$</p> <p>$= 10\left( {{{36 + 14} \over {25}}} \right)$</p> <p>$= 10 \times {{50} \over {25}} = 20$</p>

About this question

Subject: Mathematics · Chapter: Statistics · Topic: Measures of Central Tendency

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