If the mean and variance of the data $65,68,58,44,48,45,60, \alpha, \beta, 60$ where $\alpha> \beta$, are 56 and 66.2 respectively, then $\alpha^2+\beta^2$ is equal to _________.
Answer (integer)
6344
Solution
<p>$$\begin{aligned}
& \overline{\mathrm{x}}=56 \\
& \sigma^2=66.2 \\
& \Rightarrow \frac{\alpha^2+\beta^2+25678}{10}-(56)^2=66.2 \\
& \therefore \alpha^2+\beta^2=6344
\end{aligned}$$</p>
About this question
Subject: Mathematics · Chapter: Statistics · Topic: Measures of Central Tendency
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