From a group of 7 batsmen and 6 bowlers, 10 players are to be chosen for a team, which should include atleast 4 batsmen and atleast 4 bowlers. One batsmen and one bowler who are captain and vice-captain respectively of the team should be included. Then the total number of ways such a selection can be made, is
Solution
<p>1 Captain, 1 vice-captain are already present</p>
<p>$\Rightarrow$ We need to select 8 players such that atleast 3 batsman and bowler must be there</p>
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<table class="tg" style="undefined;table-layout: fixed; width: 506px"><colgroup>
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<col style="width: 129px">
<col style="width: 212px">
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<tr>
<th class="tg-7btt">Batsman</th>
<th class="tg-7btt">Bowler</th>
<th class="tg-7btt">Number of ways</th>
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<tbody>
<tr>
<td class="tg-c3ow">3</td>
<td class="tg-c3ow">5</td>
<td class="tg-c3ow">${ }^6 C_3 \cdot{ }^5 C_5=20$</td>
</tr>
<tr>
<td class="tg-c3ow">4</td>
<td class="tg-c3ow">4</td>
<td class="tg-c3ow">${ }^6 C_4 \cdot{ }^5 C_4=75$</td>
</tr>
<tr>
<td class="tg-c3ow">5</td>
<td class="tg-c3ow">3</td>
<td class="tg-c3ow">${ }^6 C_5 \cdot{ }^5 C_3=60$</td>
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</table></p>
<p>Total = 155 ways</p>
About this question
Subject: Mathematics · Chapter: Permutations and Combinations · Topic: Fundamental Counting Principle
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