The number of seven digits odd numbers, that can
be formed using all the
seven digits 1, 2, 2, 2, 3, 3,
5 is ____________.
Answer (integer)
240
Solution
<p>$.......1 \to {{6!} \over {2!3!}} = 60$</p>
<p>$.......3 \to {{6!} \over {3!}} = 120$</p>
<p>$.......5 \to {{6!} \over {3!2!}} = 60$</p>
<p>Total = 240</p>
About this question
Subject: Mathematics · Chapter: Permutations and Combinations · Topic: Permutations
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