Team 'A' consists of 7 boys and n girls and Team 'B' has 4 boys and 6 girls. If a total of 52 single matches can be arranged between these two teams when a boy plays against a boy and a girl plays against a girl, then n is equal to :
Solution
Total matches between boys of both team = ${}^7{C_1} \times {}^4{C_1} = 28$<br><br>Total matches between girls of both team = ${}^n{C_1}\,{}^6{C_1} = 6n$<br><br>Now, 28 + 6n = 52<br><br>$\Rightarrow$ n = 4
About this question
Subject: Mathematics · Chapter: Permutations and Combinations · Topic: Fundamental Counting Principle
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