If all the words with or without meaning made using all the letters of the word "NAGPUR" are arranged as in a dictionary, then the word at $315^{\text {th }}$ position in this arrangement is :
Solution
<p>NAGPUR</p>
<p>Word at $315^{\text {th }}$ position</p>
<p>$$\begin{aligned}
& \text { A...... }=5!=120 \\
& \text { G....... }=5!=120 \\
& \text { NA..... }=4!=24 \\
& \text { NG..... }=4!=24 \\
& \text { NP..... }=4!=24
\end{aligned}$$</p>
<p>..... Till 312 words</p>
<p>$313^{\text {th }} \text { word }=\text { NRAGPU }$</p>
<p>$314^{\text {th }}$ word $=$ $\mathrm{NRAGUP}$</p>
<p>$315^{\text {th }} \text { word }=\text { NRAPGU }$</p>
About this question
Subject: Mathematics · Chapter: Permutations and Combinations · Topic: Fundamental Counting Principle
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