The number of ways to distribute 30 identical candies among four children C1, C2, C3 and C4 so that C2 receives at least 4 and at most 7 candies, C3 receives at least 2 and at most 6 candies, is equal to :
Solution
<p>By multinomial theorem, no. of ways to distribute 30 identical candies among four children C<sub>1</sub>, C<sub>2</sub> and C<sub>3</sub>, C<sub>4</sub></p>
<p>= Coefficient of x<sup>30</sup> in (x<sup>4</sup> + x<sup>5</sup> + .... + x<sup>7</sup>) (x<sup>2</sup> + x<sup>3</sup> + .... + x<sup>6</sup>) (1 + x + x<sup>2</sup> ....)<sup>2</sup></p>
<p>= Coefficient of x<sup>24</sup> in $${{(1 - {x^4})} \over {1 - x}}{{(1 - {x^5})} \over {1 - x}}{{{{(1 - {x^{31}})}^2}} \over {{{(1 - x)}^2}}}$$</p>
<p>= Coefficient of x<sup>24</sup> in $(1 - {x^4} - {x^5} + {x^9}){(1 - x)^{ - 4}}$</p>
<p>$= {}^{27}{C_{24}} - {}^{23}{C_{20}} - {}^{22}{C_{19}} + {}^{18}{C_{15}} = 430$</p>
About this question
Subject: Mathematics · Chapter: Permutations and Combinations · Topic: Fundamental Counting Principle
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