A transverse wave is represented by $y=2 \sin (\omega t-k x)\, \mathrm{cm}$. The value of wavelength (in $\mathrm{cm}$) for which the wave velocity becomes equal to the maximum particle velocity, will be :
Solution
<p>${\omega \over k} = A\omega$</p>
<p>$\Rightarrow k = {1 \over A} = {1 \over {2\,cm}}$</p>
<p>$\Rightarrow {{2\pi } \over \lambda } = {1 \over {2\,cm}}$</p>
<p>$\Rightarrow \lambda = 4\pi \,cm$</p>
About this question
Subject: Physics · Chapter: Waves · Topic: Wave Motion and Types
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