Easy MCQ +4 / -1 PYQ · JEE Mains 2022

The equations of two waves are given by :

y1 = 5 sin 2$\pi$(x - vt) cm

y2 = 3 sin 2$\pi$(x $-$ vt + 1.5) cm

These waves are simultaneously passing through a string. The amplitude of the resulting wave is :

  1. A 2 cm Correct answer
  2. B 4 cm
  3. C 5.8 cm
  4. D 8 cm

Solution

<p>${y_1} = 5\sin (2\pi x - 2\pi vt)$</p> <p>${y_2} = 3\sin (2\pi x - 2\pi vt + 3\pi )$</p> <p>$\Rightarrow$ Phase difference = 3$\pi$</p> <p>$\Rightarrow {A_{net}} = \sqrt {A_1^2 + A_2^2 + 2{A_1}{A_2}\cos (3\pi )}$</p> <p>$\Rightarrow {A_{net}} = 2$ cm</p>

About this question

Subject: Physics · Chapter: Waves · Topic: Wave Motion and Types

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