Easy MCQ +4 / -1 PYQ · JEE Mains 2022

Which of the following equations correctly represents a travelling wave having wavelength $\lambda$ = 4.0 cm, frequency v = 100 Hz and travelling in positive x-axis direction?

  1. A $y = A\sin [(0.50\,\pi \,c{m^{ - 1}})x - (100\,\pi \,{s^{ - 1}})t]$
  2. B $y = A\sin \,\,2\pi [(0.25\,\,c{m^{ - 1}})x - (50\,{s^{ - 1}})t]$
  3. C $$y = A\sin \left[ {\left( {{{2\pi } \over 4}\,c{m^{ - 1}}} \right)x - \left( {{{2\pi } \over {100}}\,{s^{ - 1}}} \right)t} \right]$$
  4. D $y = A\sin \,\pi [(0.5\,\,c{m^{ - 1}})x - (200\,\,{s^{ - 1}})t]$ Correct answer

Solution

<p>We know, equation of wave travelling in positive x-direction is -</p> <p>$y = A\sin (kx - wt)$</p> <p>where $k = {{2\pi } \over \lambda }$</p> <p>and $w = 2\pi f$</p> <p>Here given $\lambda$ = 4 cm and frequency (f) = 100 Hz</p> <p>$\therefore$ $k = {{2\pi } \over 4} = 0.5\pi$ cm<sup>$-$1</sup></p> <p>and $w = 2\pi \times 100 = 200\pi$ s<sup>$-$1</sup></p> <p>$\therefore$ Equation of travelling wave,</p> <p>$y = A\sin (0.5\pi x - 200\pi t)$</p>

About this question

Subject: Physics · Chapter: Waves · Topic: Wave Motion and Types

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