In the wave equation
$y=0.5 \sin \frac{2 \pi}{\lambda}(400 \mathrm{t}-x) \,\mathrm{m}$
the velocity of the wave will be:
Solution
<p>${v_{wave}} = \left| {{{coefficient\,of\,t} \over {coefficient\,of\,x}}} \right|$</p>
<p>$= {{400} \over 1} = 400$ m/s</p>
About this question
Subject: Physics · Chapter: Waves · Topic: Wave Motion and Types
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