Two identical strings X and Z made of same material have tension TX and TZ in them. If their fundamental frequencies are 450 Hz and 300 Hz, respectively, then the ratio TX/TZ is
Solution
f = ${1 \over {2l}}\sqrt {{T \over \mu }}$
<br><br>For identical string $l$ and $\mu$ will be same
<br><br>f $\propto$ $\sqrt T$
<br><br>$\therefore$ ${{450} \over {300}} = \sqrt {{{{T_x}} \over {{T_y}}}}$
<br><br>$\Rightarrow$ ${{{{T_x}} \over {{T_y}}} = {9 \over 4}}$ = 2.25
About this question
Subject: Physics · Chapter: Waves · Topic: Wave Motion and Types
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