The first overtone frequency of an open organ pipe is equal to the fundamental frequency of a closed organ pipe. If the length of the closed organ pipe is 20 cm. The length of the open organ pipe is _____________ cm.
Answer (integer)
80
Solution
<p>$$2 \times \left( {{V \over {2{L_0}}}} \right) = \left( {{V \over {4{L_c}}}} \right)$$</p>
<p>$\Rightarrow {L_0} = 4{L_c}$</p>
<p>$= 4 \times 20$</p>
<p>$= 80$ cm</p>
About this question
Subject: Physics · Chapter: Waves · Topic: Wave Motion and Types
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