For a transverse wave travelling along a straight line, the distance between two peaks (crests) is 5 m, while the distance between one crest and one trough is 1.5 m. The possible wavelengths (in m) of the are :
Solution
$1.5 = \left( {2{n_1} + 1} \right){\lambda \over 2}$ ......(1)
<br><br>5 = n<sub>2</sub>$\lambda$ .....(2)
<br><br>(1) $\div$ (2)
<br><br>${{1.5} \over 5} = {{\left( {2{n_1} + 1} \right)} \over {2{n_2}}}$
<br><br>$\Rightarrow$ 3n<sub>2</sub> = 10n<sub>1</sub> + 5
<br><br>n<sub>1</sub> = 1 ; n<sub>2</sub> = 5 $\Rightarrow$ $\lambda$ = 1
<br><br>n<sub>1</sub> = 4 ; n<sub>2</sub> = 15 $\Rightarrow$ $\lambda$ = 1/3
<br><br>n<sub>1</sub> = 7 ; n<sub>2</sub> = 25 $\Rightarrow$ $\lambda$ = 1/5
About this question
Subject: Physics · Chapter: Waves · Topic: Wave Motion and Types
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