A wire of length L and mass per unit length 6.0 × 10–3 kgm–1 is put under tension of 540 N. Two consecutive frequencies that it resonates at are : 420 Hz and 490 Hz. Then L in meters is :
Solution
Fundamental frequency = 70 Hz.
<br><br>70 = ${1 \over {2l}}\sqrt {{T \over \mu }}$
<br><br>$\Rightarrow$ $l$ = 2.14 m
About this question
Subject: Physics · Chapter: Waves · Topic: Wave Motion and Types
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