Easy MCQ +4 / -1

The maximum possible efficiency of a heat engine working between a hot reservoir at $T_1$ and a cold reservoir at $T_2$ is:

  1. A $1 - T_1/T_2$
  2. B $1 - T_2/T_1$ Correct answer
  3. C $T_1/T_2$
  4. D $T_2 - T_1$

Solution

Carnot efficiency $\eta = 1 - T_c/T_h$.

About this question

Subject: Physics · Chapter: Thermodynamics · Topic: Carnot Engine

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