Easy MCQ +4 / -1

The work done by a gas in an isobaric expansion from $V_1$ to $V_2$ at pressure $P$ is:

  1. A $P(V_2 - V_1)$ Correct answer
  2. B $V(P_2 - P_1)$
  3. C $nRT\ln(V_2/V_1)$
  4. D $0$

Solution

$W = \int P\,dV = P(V_2-V_1)$ when $P$ is constant.

About this question

Subject: Physics · Chapter: Thermodynamics · Topic: Thermodynamic Processes

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