"Two particles of equal mass m have respective initial velocities $u\widehat i$ and $u\left( {{{\widehat i + \widehat j} \over 2}} \right)$. They collide completely inelastically. The energy lost in the process is :"

Question

Accepted Answer

"$\overrightarrow {{P_i}} = \overrightarrow {{P_f}}$

$\Rightarrow$ mu$\widehat i$ + m$\left( {{u \over 2}\widehat i + {u \over 2}\widehat j} \right)$ = 2m$\overrightarrow v$

Compare both side

$\overrightarrow v =$ ${{3u} \over 4}\widehat i + {u \over 4}\widehat j$

$\Rightarrow$ ${\left| {\overrightarrow v } \right|^2}$ = ${{10{u^2}} \over {16}}$

$\Delta$KE = KE_f – KE_i

= ${1 \over 2}2m \times {{10{u^2}} \over {16}}$ - ${1 \over 2}m{u^2}$ - ${1 \over 2}m{\left( {{u \over {\sqrt 2 }}} \right)^2}$

= $- {1 \over 8}m{u^2}$"

Two particles of equal mass m have respective
initial velocities $u\widehat i$ and $u\left( {{{\widehat i + \widehat j} \over 2}} \right)$.
They collide completely inelastically. The energy lost in the process is :

Solution

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Two particles of equal mass m have respective initial velocities $u\widehat i$ and $u\left( {{{\widehat i + \widehat j} \over 2}} \right)$. They collide completely inelastically. The energy lost in the process is :

Solution

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More Rotational Motion questions

Drill 25 more like these. Every day. Free.

Two particles of equal mass m have respective
initial velocities $u\widehat i$ and $u\left( {{{\widehat i + \widehat j} \over 2}} \right)$.
They collide completely inelastically. The energy lost in the process is :