If force $\overrightarrow F = 3\widehat i + 4\widehat j - 2\widehat k$ acts on a particle position vector $2\widehat i + \widehat j + 2\widehat k$ then, the torque about the origin will be :
Solution
<p>$\overrightarrow \tau = \overrightarrow r \times \overrightarrow F$</p>
<p>$$ = (2\widehat i + \widehat j + 2\widehat k) \times (3\widehat i + 4\widehat j - 2\widehat k)$$</p>
<p>$= - 10\widehat i + 10\widehat j + 5\widehat k$</p>
About this question
Subject: Physics · Chapter: Rotational Motion · Topic: Centre of Mass
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