The radius of gyration of a cylindrical rod about an axis of rotation perpendicular to its length and passing through the center will be ___________ $\mathrm{m}$.
Given, the length of the rod is $10 \sqrt{3} \mathrm{~m}$.
Answer (integer)
5
Solution
<p>$l = {{M{L^2}} \over {12}} = M{K^2}$</p>
<p>$K = {L \over {\sqrt {12} }} = {{10\sqrt 3 } \over {\sqrt {12} }} = 5\,m$</p>
About this question
Subject: Physics · Chapter: Rotational Motion · Topic: Centre of Mass
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