Easy MCQ +4 / -1 PYQ · JEE Mains 2023

A machine gun of mass $10 \mathrm{~kg}$ fires $20 \mathrm{~g}$ bullets at the rate of 180 bullets per minute with a speed of $100 \mathrm{~m} \mathrm{~s}^{-1}$ each. The recoil velocity of the gun is

  1. A $ 0.02 \mathrm{~m} / \mathrm{s}$
  2. B $1.5 \mathrm{~m} / \mathrm{s}$
  3. C $2.5 \mathrm{~m} / \mathrm{s}$
  4. D $0.6 \mathrm{~m} / \mathrm{s}$ Correct answer

Solution

<p>Momentum of bullets per unit time</p> <p>$= {{180 \times {{20} \over {1000}} \times 100} \over {60}}$ kg m/s$^2$</p> <p>= 6 N</p> <p>$\Rightarrow$ Force on gun = 6 N</p> <p>We cannot calculate recoil velocity with the given data.</p> <p>If we consider recoil velocity at $t = 1$ s, then</p> <p>${V_{\mathrm{recoil}}} = u + at$</p> <p>$= 0 + {6 \over {10}} \times 1$ = 0.6 m/s</p>

About this question

Subject: Physics · Chapter: Rotational Motion · Topic: Centre of Mass

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