The torque of a force $5 \hat{i}+3 \hat{j}-7 \hat{k}$ about the origin is $\tau$. If the force acts on a particle whose position vector is $2 i+2 j+k$, then the value of $\tau$ will be
Solution
$\vec{\tau}=\left|\begin{array}{ccc}\hat{i} & \hat{j} & \hat{k} \\ 2 & 2 & 1 \\ 5 & 3 & -7\end{array}\right|$
<br/><br/>$$
\begin{aligned}
&=\hat{i}(-14-3)+\hat{j}(5+14)+\hat{k}(6-10) \\\\
&=-17 \hat{i}+19 \hat{j}-4 \hat{k}
\end{aligned}
$$
About this question
Subject: Physics · Chapter: Rotational Motion · Topic: Centre of Mass
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