A ball of mass $0.15 \mathrm{~kg}$ hits the wall with its initial speed of $12 \mathrm{~ms}^{-1}$ and bounces back without changing its initial speed. If the force applied by the wall on the ball during the contact is $100 \mathrm{~N}$, calculate the time duration of the contact of ball with the wall.
Solution
<p>F = 100 N</p>
<p>$\Delta$P = 2 $\times$ 0.15 $\times$ 12</p>
<p>= 3.6</p>
<p>$\Rightarrow$ t = ${{3.6} \over {100}}$ = 0.036 s</p>
About this question
Subject: Physics · Chapter: Rotational Motion · Topic: Impulse and Momentum
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