A car is moving on a horizontal curved road with radius 50 m. The approximate maximum speed of car will be, if friction between tyres and road is 0.34. [take g = 10 ms$^{-2}$]
Solution
$f_{s}=\frac{m v^{2}}{r}$
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For maximum speed in safe turning,
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$\mathrm{f}_{\mathrm{s}}=\mathrm{f}_{\mathrm{s}} \max =\mu \mathrm{mg}$
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$\mathrm{v}_{\max }$ (for safe turning) $=\sqrt{\mu \mathrm{rg}}$
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$=\sqrt{0.34 \times 50 \times 10} \approx 13 \mathrm{~m} / \mathrm{s}$
About this question
Subject: Physics · Chapter: Rotational Motion · Topic: Torque and Angular Momentum
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