A body of mass $1000 \mathrm{~kg}$ is moving horizontally with a velocity $6 \mathrm{~m} / \mathrm{s}$. If $200 \mathrm{~kg}$ extra mass is added, the final velocity (in $\mathrm{m} / \mathrm{s}$) is:
Solution
<p>Momentum will remain conserve</p>
<p>$$\begin{aligned}
& 1000 \times 6=1200 \times v \\
& v=5 \mathrm{~m} / \mathrm{s}
\end{aligned}$$</p>
About this question
Subject: Physics · Chapter: Rotational Motion · Topic: Centre of Mass
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