In a uniform magnetic field, the magnetic needle has a magnetic moment 9.85 $\times$ 10$-$2 A/m2 and moment of inertia 5 $\times$ 10$-$6 kg m2. If it performs 10 complete oscillations in 5 seconds then the magnitude of the magnetic field is _______________ mT. [Take $\pi$2 as 9.85]
Answer (integer)
8
Solution
$T = 2\pi \sqrt {{I \over {MB}}}$<br><br>B = 80 $\times$ 10<sup>$-$4</sup> = 8 mT
About this question
Subject: Physics · Chapter: Magnetism · Topic: Bar Magnet and Magnetic Field
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