Easy MCQ +4 / -1 PYQ · JEE Mains 2022

A bar magnet having a magnetic moment of 2.0 $\times$ 105 JT$-$1, is placed along the direction of uniform magnetic field of magnitude B = 14 $\times$ 10$-$5 T. The work done in rotating the magnet slowly through 60$^\circ$ from the direction of field is :

  1. A 14 J Correct answer
  2. B 8.4 J
  3. C 4 J
  4. D 1.4 J

Solution

<p>$U = - \overrightarrow M \,.\,\overrightarrow B$</p> <p>So ${U_f} - {U_i} = - MB(1 - \cos \theta )$</p> <p>$= - 14J$</p> <p>So $W = - \Delta U = 14J$</p>

About this question

Subject: Physics · Chapter: Magnetism · Topic: Bar Magnet and Magnetic Field

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