A bar magnet having a magnetic moment of 2.0 $\times$ 105 JT$-$1, is placed along the direction of uniform magnetic field of magnitude B = 14 $\times$ 10$-$5 T. The work done in rotating the magnet slowly through 60$^\circ$ from the direction of field is :
Solution
<p>$U = - \overrightarrow M \,.\,\overrightarrow B$</p>
<p>So ${U_f} - {U_i} = - MB(1 - \cos \theta )$</p>
<p>$= - 14J$</p>
<p>So $W = - \Delta U = 14J$</p>
About this question
Subject: Physics · Chapter: Magnetism · Topic: Bar Magnet and Magnetic Field
This question is part of PrepWiser's free JEE Main question bank. 52 more solved questions on Magnetism are available — start with the harder ones if your accuracy is >70%.