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Solution
Let apparent dip $\theta$<sub>$a$</sub>.
<br><br>$\tan ({\theta _a}) = {{\tan ({\theta _T})} \over {\cos \phi }}$<br><br>$\Rightarrow {\theta _a} \ge {\theta _T}$<br><br>$\therefore$ True dip is less than apparent dip.
About this question
Subject: Physics · Chapter: Magnetism · Topic: Bar Magnet and Magnetic Field
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