A solenoid of 1200 turns is wound uniformly in a single layer on a glass tube 2 m long and 0.2 m in diameter. The magnetic intensity at the center of the solenoid when a current of 2 A flows through it is :
Solution
Number of turns per unit length $=\frac{1200}{2}=600$
<br/><br/>
So, Magnetic Intensity $H=n I$
<br/><br/>
$$
\begin{aligned}
& =600 \times 2 ~\mathrm{Am}^{-1} \\\\
& =1200 ~\mathrm{Am}^{-1}
\end{aligned}
$$
About this question
Subject: Physics · Chapter: Magnetism · Topic: Bar Magnet and Magnetic Field
This question is part of PrepWiser's free JEE Main question bank. 52 more solved questions on Magnetism are available — start with the harder ones if your accuracy is >70%.