The susceptibility of a paramagnetic material is 99. The permeability of the material in Wb/A-m, is :
[Permeability of free space $\mu$0 = 4$\pi$ $\times$ 10$-$7 Wb/A-m]
Solution
<p>$\mu$<sub>r</sub> = x + 1</p>
<p>= 99 + 1 = 100</p>
<p>$\Rightarrow$ $\mu$ = $\mu$<sub>r</sub>$\mu$<sub>0</sub> = 100 $\times$ 4$\mu$ $\times$ 10<sup>$-$7</sup> Wb/Am</p>
<p>= 4$\mu$ $\times$ 10<sup>$-$5</sup> Wb/Am</p>
About this question
Subject: Physics · Chapter: Magnetism · Topic: Bar Magnet and Magnetic Field
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