At a certain place the angle of dip is 30$^\circ$ and the horizontal component of earth's magnetic field is 0.5 G. The earth's total magnetic field (in G), at that certain place, is :
Solution
<p>${B_H} = B\cos 30^\circ$</p>
<p>$\Rightarrow B = {1 \over {\sqrt 3 }}G$</p>
About this question
Subject: Physics · Chapter: Magnetism · Topic: Bar Magnet and Magnetic Field
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