A force on an object of mass 100 g is $\left( {10\widehat i + 5\widehat j} \right)$ N. The position of that object at t = 2 s is $\left( {a\widehat i + b\widehat j} \right)$ m after starting from rest. The value of ${a \over b}$ will be ___________.
Answer (integer)
2
Solution
<p>$\overrightarrow F = m\overrightarrow a$</p>
<p>$\Rightarrow \overrightarrow a = 100\widehat i + 50\widehat j$</p>
<p>So, $\overrightarrow S = {1 \over 2}\overrightarrow a {t^2}$</p>
<p>${1 \over 2}\left( {100\widehat i + 50\widehat j} \right){2^2}$</p>
<p>$= 200\widehat i + 100\widehat j$ m</p>
<p>so a = 200 m and b = 100 m</p>
<p>so ${a \over b} = 2$</p>
About this question
Subject: Physics · Chapter: Laws of Motion · Topic: Newton's First Law
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