Easy MCQ +4 / -1 PYQ · JEE Mains 2022

A block of mass M slides down on a rough inclined plane with constant velocity. The angle made by the incline plane with horizontal is $\theta$. The magnitude of the contact force will be :

  1. A Mg Correct answer
  2. B $\mathrm{Mg} \cos \theta$
  3. C $\sqrt{\mathrm{Mg} \sin \theta+\mathrm{Mg} \cos \theta}$
  4. D $\operatorname{Mg} \sin \theta \sqrt{1+\mu}$

Solution

<p>As the body is moving with constant velocity so forces acting on the body must be balanced.</p> <p>$\Rightarrow$ Contact force from incline should balance weight of the body.</p> <p>$\Rightarrow$ | F<sub>contact</sub> | = Mg</p>

About this question

Subject: Physics · Chapter: Laws of Motion · Topic: Newton's First Law

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