A person standing on a spring balance inside a stationary lift measures 60 kg. The weight of that person if the lift descends with uniform downward acceleration of 1.8 m/s² will be ______________ N. [g = 10 m/s²]

<p>The apparent weight $W_{\text{app}}$ of a person in an elevator moving with acceleration is given by:</p> <p>$W_{\text{app}} = m(g - a)$</p> <p>where:</p> <ul> <li>$W_{\text{app}}$ is the apparent weight,</li> <li>$m$ is the mass of the person,</li> <li>$g$ is the acceleration due to gravity,</li> <li>$a$ is the acceleration of the elevator.</li> </ul> <p>Given that the person&#39;s mass is 60 kg, the acceleration due to gravity is 10 m/s², and the acceleration of the lift is 1.8 m/s², we can substitute these values into the formula:</p> <p>$$W_{\text{app}} = 60 \, \text{kg} \times (10 \, \text{m/s}^2 - 1.8 \, \text{m/s}^2) = 60 \, \text{kg} \times 8.2 \, \text{m/s}^2 = 492 \, \text{N}$$</p> <p>So, the apparent weight of the person when the lift descends with a uniform downward acceleration of 1.8 m/s² will be 492 N.</p>