A monkey of mass $50 \mathrm{~kg}$ climbs on a rope which can withstand the tension (T) of $350 \mathrm{~N}$. If monkey initially climbs down with an acceleration of $4 \mathrm{~m} / \mathrm{s}^{2}$ and then climbs up with an acceleration of $5 \mathrm{~m} / \mathrm{s}^{2}$. Choose the correct option $\left(g=10 \mathrm{~m} / \mathrm{s}^{2}\right)$.
Solution
<p>T<sub>down</sub> = 50 $\times$ (10 $-$ 4)</p>
<p>= 50 $\times$ 6</p>
<p>= 300 N</p>
<p>T<sub>up</sub> = 50 $\times$ (10 + 5)</p>
<p>= 50 $\times$ 15</p>
<p>= 750 N</p>
<p>$\Rightarrow$ Rope will break while climbing up.</p>
About this question
Subject: Physics · Chapter: Laws of Motion · Topic: Newton's First Law
This question is part of PrepWiser's free JEE Main question bank. 56 more solved questions on Laws of Motion are available — start with the harder ones if your accuracy is >70%.