A body of mass $10 \mathrm{~kg}$ is moving with an initial speed of $20 \mathrm{~m} / \mathrm{s}$. The body stops after $5 \mathrm{~s}$ due to friction between body and the floor. The value of the coefficient of friction is:
(Take acceleration due to gravity $g=10 \mathrm{~ms}^{-2}$ )
Solution
$a=-\mu g$
<br/><br/>$$
\begin{aligned}
& \because v=u+a t \\\\
& 0=20+(-\mu \times 10) \times 5 \\\\
& 50 \mu=20 \\\\
& \mu=\frac{2}{5}=0.4
\end{aligned}
$$
About this question
Subject: Physics · Chapter: Laws of Motion · Topic: Newton's First Law
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